Answer:
Find the midsegment of the triangle which is parallel to CA.
Tip
- A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle.
- This segment has two special properties. It is always parallel to the third side, and the length of the midsegment is half the length of the third side.
- If two segments are congruent, then they have the same length or measure.In other words, congruent sides of a triangle have the same length.
We have to find the segment which is parallel to CA.
From the given data,
The segment EG is the midsegment of the triangle
ABC.
So we have,
A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle. This segment has two special properties. It is always parallel to the third side.
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Answer:
WZ = 30
Step-by-step explanation:
set up equation based on WZ = W'Z'
3/4[6x + 10] = 13x - 35
multiply each side of equation by 4 to eliminate fractions:
18x + 30 = 52x - 140
-34x = -170
x = 5
substitute 5 for 'x' in either expression:
13(5) - 35
65 - 35 = 30
5 seconds
because that is the positive zero of that equation
Here is the information we have:
1. The perimeter is at most 130 cm.
2. The length of the rectangle is 4 times the width.
We can let l stand for length and w for width.
The formula for the perimeter of a rectangle is 2l + 2w.
We have to change the formula a bit.
The length of this rectangle is going to be 4 times the width
So, replace 2l with 2(4w).
Then make this equation equal to 130.
2(4w) + 2w = 130 ; Start
8w + 2w = 130 ; Distribute the 2 across the 4w
10w = 130 ; Combine the like terms 8w and 2w
w = 13 ; Divide both sides by the coefficient of w. Which is 10
