The half-life of the reaction is 50 minutes
Data;
- Time = 43 minutes
- Type of reaction = first order
- Amount of Completion = 45%
<h3>Reaction Constant</h3>
Let the initial concentration of the reaction be X
The reactant left = (1 - 0.45) X = 0.55 X = X
For a first order reaction
<h3>Half Life </h3>
The half-life of a reaction is said to be the time required for the initial amount of the reactant to reach half it's original size.
Substitute the values
The half-life of the reaction is 50 minutes
Learn more on half-life of a first order reaction here;
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The answer is <span>C. Glucose is an organic molecule.
Glucose is carbohydrate so it cannot be a protein or a nucleic acid. It is an organic molecule. The organic molecule is compound consisting of carbon to which are attached hydrogen, oxygen, and nitrogen. Since, g</span><span>lucose is a simple sugar made up of carbon, hydrogen, and oxygen, it, as well as any other carbohydrate, is the organic molecule.</span>
<h2>The required balanced equation:</h2><h2>
</h2>
Explanation:
• Propane when reacts with oxygen it gives carbon dioxide and water.
- In order to make the equation balanced at both ends of the equation,
Add 4 as a coefficient before on L.H.S (Left Hand Side) of Equation.
• Therefore, the required balanced equation is:
Propane, when added with 5 molecules of Water, yields 3 molecules of Carbon Dioxide and 4 molecules of water, as shown in the below equation -
Answer:
See explanation below
Explanation:
In this case, we can use the Boyle's law. Assuming that the temperature of both trial remains constant, then:
P₁V₁ = P₂V₂ (1)
You should note that this expression is usable when you are dealing with gases. However, we can treat this unknown liquid as a gas, because all the air on the flask is removed, and we can assume that the liquid can behave like an ideal gas.
So using the above expression, we can solve for P₂:
P₂ = P₁V₁ / V₂ (2)
In this case, we already have the values of presures and volume, so replacing in this expression:
P₂ = 34.5 * 5 / 214
<h2>
P₂ = 0.806 kPa</h2>
This should be the pressure of the liquid.
Hope this helps