Answer:
The number of atoms in the gemstones of that tiara is .
Explanation:
Number of diamonds ion tiara = 888
Mass of each diamond = 1.0 carat = 0.200 g (given)
Mass of 888 diamonds in tiara:
Given that diamond is a form of carbon.
Atomic mass of carbon atom = 12 g/mol
Moles of 77.600 g of carbon =
Number of atoms of carbon 14.800 moles:
The number of atoms in the gemstones of that tiara is .
A polymer is a really long chain of smaller molecules (monomers). It's similar to a chain of paper clips because all of the little monomers will attach to each other, forming a long strain.
Answer:
43 mole
Explanation:
Given data:
Number of atoms of Li = 2.6× 10²⁵ atoms
Number of moles = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance. The number 6.022 × 10²³ is called Avogadro number.
1 mole = 6.022 × 10²³ atoms
2.6× 10²⁵ atoms × 1 mole / 6.022 × 10²³ atoms
0.43 × 10² mole
43 mole
Answer:
Hydrogen H₂ will be the limiting reagent.
The excess reactant that will be left after the reaction is 3.45 moles.
4.3 moles of water can be produced.
Explanation:
The balanced reation is:
2 H₂ + O₂ → 2 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:
- H₂: 2 moles
- O₂: 1 mole
- H₂O: 2 moles
To determine the limiting reagent, you can use a simple rule of three as follows: if by stoichiometry 1 mole of O₂ reacts with 2 moles of H₂, how much moles of H₂ will be needed if 5.6 moles of O₂ react?
moles of H₂= 11.2 moles
But 11.2 moles of H₂ are not available, 4.3 moles are available. Since you have less moles than you need to react with 5.6 moles of O₂, <u><em>hydrogen H₂ will be the limiting reagent</em></u> and oxygen O₂ will be the excess reagent.
Then you can apply the following rules of three:
- If by reaction stoichiometry 2 moles of H₂ react with 1 mole of O₂, 4.3 moles of H₂ will react with how many moles of O₂?
moles of O₂= 2.15 moles
The excess reactant that will be left after the reaction can be calculated as:
5.6 moles - 2.15 moles= 3.45 moles
<u><em>The excess reactant that will be left after the reaction is 3.45 moles.</em></u>
- If by reaction stoichiometry 2 moles of H₂ produce 2 moles of H₂O, 4.3 moles of H₂ produce how many moles of H₂O?
moles of H₂O= 4.3 moles
<u><em>4.3 moles of water can be produced.</em></u>
<h3><u>Answer</u>;</h3>
19 mg
<h3><u>Explanation</u>;</h3>
dose = 5.0 mg/kg
weight of infant = 8.5 pounds
Convert 8.5 pounds to kg: 8.5 pounds = 3.86 kg
Therefore;
The dose to give the infant is:
= (5.0 mg/kg) x (3.86 kg)
= 19.3 mg
<u>≈ 19 mg</u>