THIS IS THE COMPLETE QUESTION BELOW;
The weekly salaries of sociologists in the United States are normally distributed and have a known population standard deviation of 425 dollars and an unknown population mean. A random sample of 22 sociologists is taken and gives a sample mean of 1520 dollars.
Find the margin of error for the confidence interval for the population mean with a 98% confidence level.
z0.10 z0.05 z0.025 z0.01 z0.005
1.282 1.645 1.960 2.326 2.576
You may use a calculator or the common z values above. Round the final answer to two decimal places.
Answer
Margin error =210.8
Given:
standard deviation of 425
sample mean x=1520 dollars.
random sample n= 22
From the question We need to to calculate the margin of error for the confidence interval for the population mean .
CHECK THE ATTACHMENT FOR DETAILED EXPLANATION
X= -8/5y+16
y= -5/8x+10
you didnt say if the equation was "5x+8y=80" not sure if your adding or subtracting or adding but if your adding then this is correct :)
Seems like a wordplay question.
A "scale" is used for measuring length.
A different sort of "scale" is used for measuring mass.
yeah same but I'm writing an essay have fun byeeeee
Answer:
50
Step-by-step explanation:
60-10