Answer:
{-infinity, infinity}
no solution
Step-by-step explanation:
|x| +15≥4
Subtract 15 from each side
|x| +15-15≥4-15
|x| ≥-11
This is always true so x can be and real number
{-infinity, infinity}
-2|5x+3| = 8
Divide by -2
-2/-2|5x+3| = 8/-2
|5x+3| = -4
This can never happen because absolute values are zero or greater
no solution
Answer:
- 9x + 12
Step-by-step explanation:
Given
(- 7x + 4) - (2x - 8) ← distribute parenthesis by 1 and - 1
= - 7x + 4 - 2x + 8 ← collect like terms
= - 9x + 12
Answer:
5 length
Step-by-step explanation:
The diagram attached shows two equilateral triangles ABC & CDE. Since both squares share one side of the square BDFH of length 10, then their lengths will be 5 each. To obtain the largest square inscribed inside the original square BDFH, it makes sense to draw two other equilateral triangles AGH & EFG at the upper part of BDFH with length equal to 5.
So, the largest square that can be inscribe in the space outside the two equilateral triangles ABC & CDE and within BDFH is the square ACEG.
Answer:I don't know this one.
Step-by-step explanation:
Answer:
The smallest possible length is 0.83m
Step-by-step explanation:
Given
Required
The smallest length of the tank
Since the tank is cubical, then the volume is:
This gives:
Express as
Take cube roots of both sides
Rewrite as:
Approximate