HOW TO DO THIS QUESTION
2 answers:
9514 1404 393
Answer:
64.2 cm²
Step-by-step explanation:
The length AC is found from ...
Area of ACD = (1/2)(AC)(CD)
80.5 cm² = (1/2)(AC)(14 cm)
AC = 80.5 cm²/(7 cm) ≈ 11.5 cm
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The area of ∆ABC is ...
Area ABC = (1/2)(CB)(CA)sin(C)
= (1/2)(19 cm)(11.5 cm)sin(36°) ≈ 64.2 cm²
Answer:
A ≈ 40.3 cm²
Step-by-step explanation:
The area of right Δ ACD is calculated as
A = bh ( b is the base and h the perpendicular height )
Here A = 50.5, b = CD and h = AC , then
× 14 × AC = 50.5
7 AC = 50.5 ( divide both sides by 7 )
AC ≈ 7.214
The area of Δ ABC is calculated as
A = × BC × AC × sin36°
= 0.5 × 19 × 7.214 × sin36°
≈ 40.3 cm² ( to 3 sf )
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Answer:
part a and b only i was actually looking for c
Step-by-step explanation:
for part b
Area of DEF= 1/2× base × height = 1/2× 2 × 1 = 1
Area of FGD= 1/2× base × height = 1/2× 2.24 × 1.34 =1.50
Area of GBD= 1/2× base × height = 1/2× 2 × 1 = 1
Area of ABG= 1/2× base × height = 1/2× 4.12 × 0.49 =1.01
Area of BCD= 1/2× base × height = 1/2× 1.41 × 2.12 =1.49
The approximate area of the original polygon is 6 square units
