Area of a Polygon In this unit, you learned about finding the area of triangles and rectangles using coordinates. But there are
many more shapes than just triangles and rectangles, and these shapes often can be relatively complex. You can still find properties of such polygons by dividing them into an arrangement of simpler shapes—polygons that you’re familiar with. When a two-dimensional figure is composed of smaller figures, its area is equal to the sum of the areas of the smaller figures. When finding the area of a polygon, it is helpful to know that any polygon can be partitioned into a series of triangles. You will use GeoGebra to partition a polygon into a set of triangles. Go to partitioning a polygon, and complete each step below. Part A Draw line segments to partition the given polygons into triangles. There is more than one correct answer. Take a screenshot of your construction, save it, and insert the image in the space below. Part B Think back to Task 1 of these Lesson Activities. Finding the area of a polygon using only coordinates can be tedious. Fortunately, you do have access to additional tools that help you find the area of a polygon while following the same basic methods. This is especially helpful when polygons are irregular or have many sides. Next you will use GeoGebra to find the area of a polygon divided into a set of triangles. Go to area of a polygon, and complete each step below: Partition the polygon into triangles by drawing line segments between vertices. For each triangle, draw an altitude to represent the height of the triangle. Place a point at the intersection of the height and the base of each triangle. Use the tools in GeoGebra to find the length of the base and the height of each triangle. (Because the values displayed by GeoGebra are rounded, your result will be approximate.) Compute the area of each triangle, and record the results below. Show your work. Add the areas of the triangles to determine the area of the original polygon, and note your answer below. When you’re through, take a screenshot of your construction, save it, and insert the image below your answers. Part C In part B, you used a combination of GeoGebra tools and manual calculations to find the approximate area of the original polygon. Now try using the more advanced area tools in GeoGebra to verify your answer in part B. Which method did you choose? Do your results in parts B and C match?
1 answer:
Answer:
part a and b only i was actually looking for c
Step-by-step explanation:
for part b
Area of DEF= 1/2× base × height = 1/2× 2 × 1 = 1
Area of FGD= 1/2× base × height = 1/2× 2.24 × 1.34 =1.50
Area of GBD= 1/2× base × height = 1/2× 2 × 1 = 1
Area of ABG= 1/2× base × height = 1/2× 4.12 × 0.49 =1.01
Area of BCD= 1/2× base × height = 1/2× 1.41 × 2.12 =1.49
The approximate area of the original polygon is 6 square units
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Answer:
(c, m) = (45, 10)
Step-by-step explanation:
A dozen White Chocolate Blizzards generate more income and take less flour than a dozen Mint Breezes, so production of those should clearly be maximized. Making 45 dozen Blizzards does not use all the flour, so the remaining flour can be used to make Breezes.
Maximum Blizzards that can be made: 45 dz. Flour used: 45×5 oz = 225 oz.
The remaining flour is ...
315 oz -225 oz = 90 oz
This is enough for (90 oz)/(9 oz/dz) = 10 dozen Mint Breezes. This is in the required range of 2 to 15 dozen.
Kelly should make 45 dozen White Chocolate Blizzards and 10 dozen Mint Breezes: (c, m) = (45, 10).
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In the attached graph, we have reversed the applicable inequalities so the feasible region shows up white, instead of shaded with 5 different colors. The objective function is the green line, shown at the point that maximizes income. (c, m) ⇔ (x, y)
