(sample g/1) X (1 mole/40.078(MW of Ca)) = moles of sample (moles of sample)(6.022 x 10^23( no of atoms)/ 1 mole) = # of atoms in a 120 g sample of calcium Avogadro's number=6.022x 10^23 atoms in 1 mole
The answer for the following question is explained.
<u><em>Therefore the number of electrons present with the values n = 5, l = 2, m = -2, s = +1/2 is</em></u><u> </u><u><em>one(1).</em></u>
Explanation:
Here;
n represents the principal quantum number
l represents the Azimuthal quantum number
m represents magnetic quantum number
s represents spin quantum number
n = 5,
l = 2,
m = -2,
s = +1/2
Here, it implies 5d orbital.
In the 5d orbital, 10 electrons.
As the magnetic quantum number is -2, and so it can have 1 electron.
<u><em>Therefore the number of electrons present with the values n = 5, l = 2, m = -2, s = +1/2 is</em></u><u> </u><u><em>one(1)</em></u>
Answer:
false
Explanation:
not all science is good, or has good effects
So they can tell what exact species it is.
Answer:
Approximately .
Explanation:
The gallium here is likely to be produced from a solution using electrolysis. However, the problem did not provide a chemical equation for that process. How many electrons will it take to produce one mole of gallium?
Note the Roman Numeral "" next to . This numeral indicates that the oxidation state of the gallium in this solution is equal to . In other words, each gallium atom is three electrons short from being neutral. It would take three electrons to reduce one of these atoms to its neutral, metallic state in the form of .
As a result, it would take three moles of electrons to deposit one mole of gallium atoms from this gallium solution.
How many electrons are supplied? Start by finding the charge on all the electrons in the unit coulomb. Make sure all values are in their standard units.
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Calculate the number of electrons in moles using the Faraday's constant. This constant gives the size of the charge (in coulombs) on each mole of electrons.
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It takes three moles of electrons to deposit one mole of gallium atoms . As a result, of electrons would deposit of gallium atoms .