Answer:
students who want to go to Brentview Arts must fill out an online application
Explanation:
if the only way to get into Brentview Arts is by doing an application online, then computers would help those students. They can't send it through the mail so the computer would be their only resource
First, preexisting rocks must weather/erode, forming the sediment that will eventually form the sedimentary rock. Then, that sediment must settle someplace, and over a long period of time, pressure begins to build. This causes the sediments to become compacted. After a long period of time (and a lot of pressure), the sediments cement together and form a sedimentary rock. In a nutshell, sedimentary rocks form through compaction, cementation, and eventually... lithification.
Hope that helped! <span />
C. Solutions are mixtures with an even, or homogenous, distribution.<span>
</span>
“A carnivore eats both a
rabbit and a mouse in a food web” accurately describes a difference
between a food chain and a food web.
<span>A food chain is a series of events in which one
organism eats another and obtains energy. An example could be a forest
food-chain. The bear is the top of the food chain. The bear eats a coyote. The
coyote ate the rabbit. The rabbit ate the grass. Since the grass can't
technically eat anything, it's the bottom of the food chain and the food chain
ends. </span>
<span>A food web is a diagram showing the various
different plants and animals in an ecosystem in relation to each other. It
encompasses many consumers of each different level, acknowledging that one
predator may eat several different kinds of prey, and that one kind of prey may
be eaten by several kinds of predators. There are many food chains within a
food web, and one creature is not necessarily at the top of the hierarchy. </span>
The correct answer between all
the choices given is the second choice or letter B. I am hoping that this
answer has satisfied your query and it will be able to help you in your
endeavor, and if you would like, feel free to ask another question.
