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I typed right on the problem set.
Answer:
03%
Step-by-step explanation:
In this situation Mickey should have drew first 7 cards that are not diamond and then on the 8th attempt she should draw an ace.
Let A be the event of drawing 7 cards which are not diamond and B the event of drawing an ace card. therefore required probability is P(A∩B)=P(A)*P(B)
Now, there are 13 diamonds and 39 other cards. Hence,
P(A)=()⁷=0.1335
After drawing 7 non-diamond cards, the 8th card must be a diamond.Hence,
P(B)==0.25
Hence, P(A∩B)=P(A)*P(B)=0.1335*0.25=0.033(approximately 0.03,i.e. 3%)
Therefore probability that Mickey will draw her first diamond on the 8th
attempt is 3%