First of all we will understand the question!!
<em>The</em><em> </em><em>question</em><em> </em><em>is</em><em> </em><em>saying</em><em> </em><em>that</em><em> </em><em>you</em><em> </em><em>are</em><em> </em><em>given</em><em> </em><em>a</em><em> </em><em>function</em><em> </em><em>and</em><em> </em><em>you</em><em> </em><em>have</em><em> </em><em>to</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>x</em><em> </em><em>which</em><em> </em><em>will</em><em> </em><em>give</em><em> </em><em>the</em><em> </em><em>maximum</em><em> </em><em>profit</em><em>.</em><em>.</em><em>.</em><em> </em><em>Lets</em><em> </em><em>solve</em><em> </em><em>it</em><em> </em><em>by</em><em> </em><em>finding</em><em> </em><em>the</em><em> </em><em>extrema</em><em> </em><em>using</em><em> </em><em>the</em><em> </em><em>vertex</em>
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- <u>Identify the coefficients a and b of the quadratic function</u>
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- <u>Since a<0, the function has the maximum value at x, calculated by substituting a and b into x=-b/2a</u>
<u></u>
- <u>Solve</u><u> </u><u>the</u><u> </u><u>equation</u><u> </u><u>for</u><u> </u><u>x</u><u> </u>
<u></u>
- <u>The maximum of the quadratic function is at </u><u>x</u><u>=</u><u>3</u>
Another way to ask this question: where the x-value of function g equals 12, what's the y-value?
remember that function notation is like so: f(x), g(x), h(x)... so the number in the parentheses is an x-value from the function.
look through your points and find the one that represents an x-value of 12. (12, 19) is the point, and 19 is your output--so, g(12) = 19.
Are you doing online school? I am and i need this as well :(
Answer:
Step-by-step explanation:
Solve for the mean (average) of the five test scores.
Subtract that mean from each of the five original test scores. Square each of the differences.
Find the mean (average) of each of these differences you found in Step 2.
Take the square root of this final mean from #3. This is the standard deviation.
Answer:
C:
Step-by-step explanation:
Did this through my TI-89 calculator. ^^