20 POINTS!!
1 answer:
9514 1404 393
Answer:
P = 3x +32
Step-by-step explanation:
If we assume the short vertical edge at top center is 10 yards, as it was in two previous problems with this geometry, then we can find the area of the present parking lot as ...
(x-2)(3x) + x(3x -10) +2x(40) = 6x^2 +64x
where the left vertical rectangle is 3x high and x-2 wide; the center area between vertical rectangles is (2x-2)-(x-2) = x wide and (3x-10) high; and the right vertical rectangle is (x-2 +3x)-(2x-2) = 2x wide and 40 high.
As we said, the right vertical rectangle is 2x wide, so the area that has P as one of its dimensions is ...
A = LW = P(2x)
We want this to be the same as the existing area, so ...
2Px = 6x^2 +64x
P = 3x +32 . . . . . divide by 2x
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Therefore, the conclusion is valid.
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Step-by-step explanation:
Consider the provided statement.
Premises: All good students are good readers. Some math students are good students.
Conclusion: Some math students are good readers.
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Now, it is given that some math students are good students, that means there exist some math student who are good students as well as good reader.
Therefore, the conclusion is valid.
The required diagram is shown below:
