The molarity of the stock solution is 1.25 M.
<u>Explanation:</u>
We have to find the molarity of the stock solution using the law of volumetric analysis as,
V1M1 = V2M2
V1 = 150 ml
M1 = 0.5 M
V2 = 60 ml
M2 = ?
The above equation can be rearranged to get M2 as,
M2 =
Plugin the values as,
M2 =
= 1.25 M
So the molarity of the stock solution is 1.25 M.
Answer:
Explanation:
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In this case, according to the given chemical reaction, it possible for us to set up the expression for the calculation of the enthalpy change as shown below:
Thus, given the values of the enthalpies of formation on the attached file, we obtain:
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The reaction is:
So for every molecule of nitrogen we need 3 molecules of hydrogen.
Now, we have 4 molecules of nitrgen, so if the total amount of nitrogen react we would need 4x3=12 molecules of hydrogen.
We know that there are only 9 molecules of hydrogen present, so it is not possible that all the nitrogen present react. Therefore the limiting reactant is hydrogen.
To answer how many molecules of ammonia (NH3) are produced we need to calculate the amount formed if all the hydrogen present reacts:
For every 3 molecules of hydrogen 2 molecules of ammonia are formed, so for 9 molecules of hydrogen the molecules of ammonia formed are: 2x3=6.
To form 6 molecules of ammonia there are needed 6/2=3 molecules of nitrogen, so only one remains after the reaction.
To summerize:
• The number of molecules of ammonia formed are 6
,
• The limiting reactant is hydrogen
,
• The number of molecules remaining after the reaction are:
molecules of hydrogen: 0
molecules of nytrogen: 1