The magnitude of the electrostatic force between two charges is given by:
where
ke is the Coulomb's constant
q1 and q2 are the two charges
r is the separation between the two charges
We can see that the magnitude of the force is directly proportional to the charges. This means that when one of the charges is doubled, the magnitude of the electrostatic force will double as well, so the correct answer is
A) <span>The magnitude of the electrostatic force doubles</span>
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Answer:
Explanation:
<u>Displacement</u>
It is a vector that points to the final point where an object traveled from its starting point. If the object traveled to several points, then the individual displacements must be added as vectors.
The mail carrier leaves the post office and drives 2 km due north. The first displacement vector is
Then the carrier drives 7 km in 60° south of east. The displacement has two components in the x and y axis given by
Finally, he drives 9.5 km 35° north of east.
The total displacement is
The direction can be calculated with
Explanation:
Let yellow ball be m1 = 0.5kg with u1 = 8 m/s and blue ball be m2 = 0.25 kg with u2 = - 4 m /s respectively.
After collision, blue ball travels 12 m/s.
<u>Using conservation of Linear Momentum</u> :
m1u1 + m2u2 = m1v1 + m2v2
0.5* 8 + 0.25 * - 4 = 0.5 * v1 + 0.25 * 12
v1 = 0 m/sec i.e. <u>Yellow ball comes to rest</u>.