Answer:
r = 0.05 m = 5 cm
Explanation:
Applying ampere's law to the wire, we get:
where,
r = distance of point P from wire = ?
μ₀ = permeability of free space = 4π x 10⁻⁷ N/A²
I = current = 2 A
B = Magnetic Field = 8 μT = 8 x 10⁻⁶ T
Therefore,
<u>r = 0.05 m = 5 cm</u>
Answer:
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Answer:
Distance, d = 0.1 m
It is given that,
Initial velocity of meson,
Finally, the meson is coming to rest v = 0
Acceleration of the meson, (opposite to initial velocity)
Using third equation of motion as :
s is the distance the meson travelled before coming to rest.
So,
s = 0.1 m
The meson will cover the distance of 0.1 m before coming to rest. Hence, this is the required solution.
Answer:
The average acceleration of the ball during the collision with the wall is
Explanation:
<u>Known Data</u>
We will asume initial speed has a negative direction, , final speed has a positive direction, , and mass .
<u>Initial momentum</u>
<u>final momentum</u>
<u>Impulse</u>
<u>Average Force</u>
<u>Average acceleration</u>
, so .
Therefore,
Answer:
The frequency of sound wave created by trumpet is 437.5Hz
Explanation:
Given
the speed of sound wave = 350 m
the wavelength of sound wave = 0.8 m
the frequency of sound wave = ?
All the waves have same relationship among wavelength, frequency and speed, which is given by the equation:
v = fλ, where
v is speed of the wave
f is frequency of the wave
λ is wavelength of the wave
therefore frequency of sound wave is given by
f = v/λ
= 350m/0.8m
= 437.5
= 437.5Hz (since 1 = 1 Hz (Hertz)
Hence the frequency of sound wave created by trumpet is 437.5Hz