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Answer:g=9.79,A object of mass
at the surface of earth experiences a force
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Explanation:
Let be the mass of earth.
Let be the radius of earth.
Let be the universal gravitational constant.
Given,
Let be the acceleration due to gravity.
Then,
A object of mass at the surface of earth experiences a force
Answer:
The Greenhouse Effect Revisited. When solar energy strikes the planet during the day, the ground, highways and other objects get hot and absorb that energy. As the sun goes down, the Earth cools by giving off infrared radiation. Because greenhouse gases absorb part of this radiation, the atmosphere warms and keeps the Earth from getting too cold.
<span>What we need to first do is split the ball's velocity into vertical and horizontal components. To do that multiply by the sin or cos depending upon if you're looking for the horizontal or vertical component. If you're uncertain as to which is which, look at the angle in relationship to 45 degrees. If the angle is less than 45 degrees, the larger value will be the horizontal speed, if the angle is greater than 45 degrees, the larger value will be the vertical speed. So let's calculate the velocities
sin(35)*18 m/s = 0.573576436 * 18 m/s = 10.32437585 m/s
cos(35)*18 m/s = 0.819152044 * 18 m/s = 14.7447368 m/s
Since our angle is less than 45 degrees, the higher velocity is our horizontal velocity which is 14.7447368 m/s.
To get the x positions for each moment in time, simply multiply the time by the horizontal speed. So
0.50 s * 14.7447368 m/s = 7.372368399 m
1.00 s * 14.7447368 m/s = 14.7447368 m
1.50 s * 14.7447368 m/s = 22.1171052 m
2.00 s * 14.7447368 m/s = 29.48947359 m
Rounding the results to 1 decimal place gives
0.50 s = 7.4 m
1.00 s = 14.7 m
1.50 s = 22.1 m
2.00 s = 29.5 m</span>
renewable: water, plants, animals
nonrenewable: rocks, soil
i hope this helps :)
Answer:
s = 11.78 m
Explanation:
given,
acceleration due to gravity, g = 3.77 m/s²
mass of the rock = 15 g
time = 2.5 s
distance traveled = ?
using equation of motion
initial speed = 0 m/s
s = 11.78 m
distance traveled by the rock is equal to 11.78 m.