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2 years ago

Carlita planted 4 flowers in 6 minutes. About how many flowers can Carlita plant in 36 minutes?

Mathematics

2 answers:

sattari [20]2 years ago

6 0

Answer:

Step-by-step explanation:

$\frac{4}{6} =\frac{x}{36}$

$\frac{4}{6} *\frac{6}{6} =\frac{24}{36}$

$x = 24$

Hope this helps and pls do mark me brainliest if you can:)

Ne4ueva [31]2 years ago

4 0

Answer:

Step-by-step explanation:

6*6=36, so she has 6 times as much time to plant with 36 minutes.

4*6=24, so she can plant 24 flowers in 36 minutes.

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The speed limit on a highway is 70 miles per hour. About how fast is this in miles per minute?

Lady bird [3.3K]

The speed of this:
70 miles per hour

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70/60 = 7/6

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2 years ago

According to a recent survey of first-year high school students, 28% chew gum daily. The students were also asked if they had re

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4 0

2 years ago

Find the solution of the differential equation dy/dt = ky, k a constant, that satisfies the given conditions. y(0) = 50, y(5) =

irga5000 [103]

Answer: The required solution is $y=50e^{0.1386t}.$

Step-by-step explanation:

We are given to solve the following differential equation :

$\dfrac{dy}{dt}=ky~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

where k is a constant and the equation satisfies the conditions y(0) = 50, y(5) = 100.

From equation (i), we have

$\dfrac{dy}{y}=kdt.$

Integrating both sides, we get

$\int\dfrac{dy}{y}=\int kdt\\\\\Rightarrow \log y=kt+c~~~~~~[\textup{c is a constant of integration}]\\\\\Rightarrow y=e^{kt+c}\\\\\Rightarrow y=ae^{kt}~~~~[\textup{where }a=e^c\textup{ is another constant}]$

Also, the conditions are

$y(0)=50\\\\\Rightarrow ae^0=50\\\\\Rightarrow a=50$

and

$y(5)=100\\\\\Rightarrow 50e^{5k}=100\\\\\Rightarrow e^{5k}=2\\\\\Rightarrow 5k=\log_e2\\\\\Rightarrow 5k=0.6931\\\\\Rightarrow k=0.1386.$

Thus, the required solution is $y=50e^{0.1386t}.$

8 0

2 years ago

Read 2 more answers

WILL GIVE BRAINLIEST

Alona [7]

Given:

One linear function represented by the table.

Another linear function represented by the graph.

To find:

The greater unit rate and greater y-intercept.

Solution:

Formula for slope (unit rate):

$m=\dfrac{y_2-y_1}{x_2-x_1}$

From the given table it is clear that the linear function passes through (0,5) and (5,15). The function intersect the y-axis at (0,15), so the y-intercept is 15.

$m_1=\dfrac{15-5}{5-0}$

$m_1=\dfrac{10}{5}$

$m_1=2$

So, the unit rate of first function is 2.

From the given graph it is clear that the linear function passes through (0,6) and (-4,0). The function intersect the y-axis at (0,6), so the y-intercept is 6.

$m_2=\dfrac{0-6}{-4-0}$

$m_2=\dfrac{-6}{-4}$

$m_2=\dfrac{3}{2}$

So, the unit rate of first function is $\dfrac{3}{2}$ .

Now,

$2>\dfrac{3}{2}$

$m_1>m_2$

And,

$15>6$

Therefore, the greater unit rate of the two functions is 2. The greater y-intercept of the two functions is 15.

4 0

2 years ago

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Write the explicit formula that represents the geometric sequence-2, 8, -32, 128

maks197457 [2]

Well, since we know is a geometric sequence, we can always get the common ratio of it by simply dividing one value by the one behind it... so let's do so, with say hmm -32 and 8 -32/8 = -4 <-- our common ratio

the first term is -2

$\bf n^{th}\textit{ term of a geometric sequence}\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
a_1=-2\\
r=-4
\end{cases}\implies a_n=-2(-4)^{n-1}$

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2 years ago