Can somebody help me alive this?
2 answers:
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Answer:
See explanation
Step-by-step explanation:
The surface area of the solid generated by revolving the region bounded by the graphs can be calculated using formula
If then
and
Therefore,
Apply substitution
Then
Now
Hence,
No because it would be
if you knew that
ax^2+bx+c was a trinomial square, then the factored form would be
or 
so
if w^2-9w+81 is perfect square, factored form is either
or 
aka 
or 
expand them
(x+9)^2=x^2+18x+81, wron middle term
(x-9)^2=x^2-18x+81 wrong
so it is not
if you knew that
ax^2+bx+c was a trinomial square, then the factored form would be
so
if w^2-9w+81 is perfect square, factored form is either
expand them
(x+9)^2=x^2+18x+81, wron middle term
(x-9)^2=x^2-18x+81 wrong
so it is not
Answer:
57 units^2
Step-by-step explanation:
First find the area of the triangle on the left
ABC
It has a base AC which is 9 units and a height of 3 units
A = 1/2 bh = 1/2 ( 9) *3 = 27/2 = 13.5
Then find the area of the triangle on the right
DE
It has a base AC which is 6 units and a height of 1 units
A = 1/2 bh = 1/2 ( 6) *1 = 3
Then find the area of the triangle on the top
It has a base AC which is 3 units and a height of 3 units
A = 1/2 bh = 1/2 ( 3) *3 = 9/2 = 4.5
Then find the area of the rectangular region
A = lw = 6*6 = 36
Add them together
13.5+3+4.5+36 =57 units^2
