Answer:
<h3>1.01 s</h3>
Explanation:
Using the equation of motion S = ut+1/2gt² to solve the problem where;
u is the initial velocity of the chocolate = 0m/s
t is the time taken
g is the acceleration due to gravity = 9.81m/s²
S is the height of fall = 5.0m
Substituting the given parameter into the formula to get the time t we have;
5 = 0(t)+1/2(9.81)t²
5 = 4.905t²
t² = 5/4.905
t² = 1.019
t = √1.019
t = 1.009 secs
<em>Hence it will take 1.01 secs for me to catch the chocolate bar</em>
The FREQUENCY of light remains unchanged once it leaves the source.
You could use a magnetic generator or you could use hydraulic power
A) No, the equations presented above are the product of the derivation of position and velocity when the acceleration is constant.
The equations change to polynomial function of the second degree for the description of the acceleration when described as a function of time.
B) Yes, when the acceleration is zero it is concluded that the velocity is constant, therefore they could be used to describe the position as a function of the change in velocity.
Answer:
F=4040.81 N
Explanation:
Given that
Time ,t= 2.45 ms
Mass ,m= 0.055 kg
v= 1.8 x 10² m/s = 180 m/s
We know that rate of change in the linear momentum is known as force.
Momentum P = m v
Therefore force F
F=4040.81 N
Therefore force on the ball will be 4040.81 N
