When Ag+ is combined with Na2CO3, the substances formed are Ag2CO3 and Na+. In this case, Ag performs single substitution over the element Na to form another set of substances. There are other types of reactions like double displacement, decomposition, etc.
Answer:
Due to gravitational Force the water exerts more pressure at "ground floor" than at "2nd floor".
Explanation:
Answer:
A. 2C + H₂ ⟶ CH₄
Explanation:
A. 2C + H₂ ⟶ CH₄
UNBALANCED. 2C on the left and 1C on the right
B. 2Al₂O₃ ⟶ 4Al + 3O₂
Balanced. Same number of each type of atom on each side.
C. 2H₂O₂ ⟶ 2H₂O + O₂
Balanced. Same number of each type of atom on each side.
D. 2C₂H₆ + 7O₂ ⟶ 4CO₂ + 6H₂O
Balanced. Same number of each type of atom on each side.
The solution is as follows:
K = [Partial pressure of isoborneol]/[Partial pressure of borneol] = 0.106
The molar mass of isoborneol/borneol is 154.25 g/mol
Mol isoborneol = 15 g/154.25 = 0.0972 mol
Mol borneol = 7.5 g/154.25 = 0.0486 mol
Use the ICE approach
borneol → isoborneol
I 0.0972 0.0486
C -x +x
E 0.0972 - x 0.0486 + x
Total moles = 0.1458
Using Raoult's Law,
Partial Pressure = Mole fraction*Total Pressure
[Partial pressure of isoborneol] = [(0.0972-x)/0.1458]*P
[Partial pressure of borneol] = [(0.0486+x/0.1458)]*P
0.106 = [(0.0972-x)/0.1458]*P/ [(0.0486+x/0.1458)]*P
Solving for x,
x = 0.0832
Thus,
<em>Mol fraction of borneol = (0.0486+0.0832)/0.1458 = 0.904</em>
<em>Mol fraction of isoborneol = (0.0972-0.0832)/0.1458 = 0.096</em>
Answer:
About 60.
Explanation:
Mendeleev knew of 63 elements. He wrote their properties on cards and arranged them in order of atomic mass.
That's how he discovered that the properties of elements are periodic functions of their atomic masses.