If
represent a family of surfaces for different values of the constant
. The gradient of the function
defined as
is a vector normal to the surface
.
Given <span>the paraboloid
.
We can rewrite it as a scalar value function f as follows:
The normal to the </span><span>paraboloid at any point is given by:
Also, the normal to the given plane
is given by:
Equating the two normal vectors, we have:
</span>
Since, -1 = 2 is not possible, therefore
there exist no such point <span>
on the paraboloid such that the tangent plane is parallel to the plane 3x + 2y + 7z = 2</span>
.
No.1
r=9
No.3
r=10.5ft
No.5
C=132m
No.7
C=25.12
No.9
44
No.11
264cm
No.13
97.34m
No.15
47.1
No.17
Am not sure
Hope this helps though
Answer:
b)0, yes
Step-by-step explanation:
Given:
Vectors (4,8) . (6,-3)
Finding inner product of vectors:
= 4x6 + 8x-3
=24-24
=0
Now to check the angle between them using formula a.b=|a|.|b|cosθ
|a|=
=8.9
|b|=
=6.7
Putting values of a.b=0 and |a|=8.9, |b|=6.7 in a.b=|a|.|b|cosθ we get,
0= 8.9(6.7)cosθ
cosθ =0
θ=90 degrees
Hence the two vectors are perpendicular !
Answer:
(2,-1)
y= -1
x= 2
Step-by-step explanation:
y= -2x+3
4x-3y=11
substitute the value of y into an equation
4x-3(-2x+3)=11
distribute by multiplying numbers in parenthesis by -3
4x+6x-9=11
add 4x to 6x
10x-9=11
add 9 from both sides
10x=20
divide both sides by 10
x=2
substitute the value of x into an equation
y= -2•2+3
multiply -2 to 2
y= -4+3
add -4 to 3 but 4 is negative, so subtract
y= -1
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(2,-1)
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