Answer:
partial pressure of gas D Pd = 15.5 kPa
Explanation:
As per the Dalton's law of partial pressure, in a mixture, pressure exerted by each gas when summed gives the total partial pressure exerted by mixture.
P(Total) = P1+P2+P3.....
Given P(Total) = 35.7 kPa
Partial pressure of gas A Pa = 7.8 kPa
Partial pressure of gas B Pb = 3.7 kPa
Partial pressure of gas C Pc = 8.7 kPa
There, Partial pressure of gas D Pd = P(Total) -(Pa+Pb+Pc)
Pd = 35.7-(7.8+3.7+8.7) = 35.7-20.2 kPa = 15.5 kPa
Therefore, partial pressure of gas D Pd = 15.5 kPa
Since volume and temperature are constant, this means that pressure and <u>number of moles</u> are <u>directly </u>proportional. the sample with the largest <u>number of moles</u> will have the <u>high </u>pressure.
Since, the ideal gas equation is also called ideal gas law. So, according to ideal gas equations,
PV = nRT
- P is pressure of the sample
- T is temperature
- V is volume
- n is the number of moles
- R is universal gas constant
At constant volume and temperature the equation become ,
P ∝ nR
since, R is also constant. So, conclusion of the final equation is
P ∝ n
The number of moles and pressure of the sample is directly proportion. So, on increasing number of moles in the sample , pressure of the sample also increases.
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Answer:- 0.800 moles of the gas were collected.
Solution:- Volume, temperature and pressure is given for the gas and asks to calculate the moles of the gas.
It is an ideal gas law based problem. Ideal gas law equation is used to solve this. The equation is:
PV=nRT
Since it asks to calculate the moles that is n, so let's rearrange this for n:
V = 19.4 L
T = 17 + 273 = 290 K
P = 746 mmHg
we need to convert the pressure from mmHg to atm and for this we divide by 760 since, 1 atm = 760 mmHg
P = 0.982 atm
R =
Let's plug in the values in the equation to get the moles.
n = 0.800 moles
So, 0.800 moles of the gas were collected.
Answer:
1.784 g
Explanation:
The equation of the reaction is;
NaOH(aq) + KHC8H4O4(aq) --------> KNaC8H4O4(aq) + H2O(l)
Number of moles of NaOH reacted = 17.47/1000 * 0.5000 M
Number of moles of NaOH reacted =8.735 * 10^-3 moles
From the reaction equation;
1 mole of NaOH reacted with 1 mole of KHC8H4O4
Hence, 8.735 * 10^-3 moles of NaOH reacts with 8.735 * 10^-3 moles of KHP.
So,
Mass of KHP reacted = 8.735 * 10^-3 moles * 204.2 g/mol = 1.784 g