Answer:
V₂ = 2.91 L
Explanation:
Given data:
Initial volume = 3.50 L
Initial temperature = 90.0°C (90+273 = 363 K)
Final temperature = 30.0 °C ( 30 +273 = 303 K)
Final volume = ?
Solution:
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
V₁/T₁ = V₂/T₂
3.50 L / 363 K) = V₂ / 303 K)
V₂ = 0.0096 L/K × 303 K
V₂ = 2.91 L
Answer:
To calculate the molar mass of a compound with multiple atoms, sum all the atomic mass of the constituent atoms molar mass can also be calculated by multiplying the atomic mass in amu by the molar mass constant (1 g/mol).
- Glucose = C₆H₁₂O₆.
- Atomic mass of C = 12 u
- Atomic mass of H = 1 u
- Atomic mass of O = 16 u
- Therefore, the molecular mass of glucose
- = (6 × Atomic mass of C) + (12 × Atomic mass of H) + (6 × Atomic mass of O)
- = (6 × 12) + (12 × 1) + (6 × 16) u
- = 72 + 12 + 96 u
- = 180 u
<u>Answer</u><u>:</u>
<u>1</u><u>8</u><u>0</u><u> </u><u>u</u>
Hope you could understand.
If you have any query, feel free to ask.
Answer:
moles SO42- = 0.0500 L x 0.20 M=0.010
moles Ba2+ = 0.0500 L x 0.10 M = 0.0050
Ba2+ + SO42- = BaSO4 (s)
moles SO42- in excess = 0.010 - 0.0050=0.0050
total volume = 100 mL = 0.100 L
[SO42-]= 0.0050/0.100= 0.050 M
[Na2SO4] = 2 /2 = 1 M
moles Na2SO4 = 2 M x 0.500 L = 0.500
mass Na2SO4 = 0.500 x 142 g/mol=71.0 g
moles MgBr2 = 46 /184 =0.25
moles Br- = 0.25 x 2 = 0.50
[Br-]= 0.50 / 0.50 L = 1 M