The coefficients in a balanced chemical equation are important because they give the ratio of the reactants and the products. Those ratios are fixed and when the reagents react do it in the same proportion and yield the products in the same proportion of the coefficients. Then, the coefficients are the basis for the calculations of the amount of substances that react and the amount of substances that are formed as result of the reaction.
Answer:
WCl₂, WCl₄, WCl₅, WCl₆
Explanation:
Molar Mass of Tungsten = 184 g/mol
Mass of Chlorine = 35.5 g/mol
In the first compound;
Percentage of tungsten = 72.17 %
Upon solving;
72.17 % = 184
100 % = Total mass
Total mass of compound = 254.95g
Mass of chlorine = 254.95 - 184 = 70.95 (Dividing by 35.35; This is approximately 2 Chlorine atoms.
The Formular is WCl₂
In the second compound;
Percentage of tungsten = 56.45 %
Upon solving;
56.45 % = 184
100 % = Total mass
Total mass of compound = 325.95 g
Mass of chlorine = 325.95 - 184 = 141.95g (Dividing by 35.35; This is approximately 4 Chlorine atoms.
The Formular is WCl₄
In the third compound;
Percentage of tungsten = 50.91 %
Upon solving;
50.91 % = 184
100 % = Total mass
Total mass of compound = 361.42 g
Mass of chlorine = 361.42 - 184 = 177.42 (Dividing by 35.35; This is approximately 5 Chlorine atoms.
The Formular is WCl₅
In the fourth compound;
Percentage of tungsten = 46.39 %
Upon solving;
46.39 % = 184
100 % = Total mass
Total mass of compound = 396.64 g
Mass of chlorine = 396.64 - 184 = 212.64 (Dividing by 35.35; This is approximately 6 Chlorine atoms.
The Formular is WCl₆
Answer:
58.0 g/mol
Explanation:
The reaction that takes place is:
- MCl₂ + 2AgNO₃ → 2AgCl + M(NO₃)₂
First we <u>calculate how many moles of silver chloride</u> were produced, using its <em>molar mass</em>:
- 6.41 g AgCl ÷ 143.32 g/mol = 0.0447 mol AgCl
Then we <u>convert AgCl moles into MCl₂ moles</u>, using the <em>stoichiometric ratio</em>:
- 0.0447 mol AgCl *
= 0.0224 mol MCl₂
Now we<u> calculate the molar mass of MCl₂</u>, using the original<em> mass of the sample</em>:
- 2.86 g / 0.0224 mol = 127.68 g/mol
We can write the molar mass of MCl₂ as:
- Molar Mass MCl₂ = Molar Mass of M + (Molar Mass of Cl)*2
- 127.68 g/mol = Molar Mass of M + (35.45 g/mol)*2
Finally we<u> calculate the molar mass</u> of M:
- Molar Mass of M = 57 g/mol
The closest option is 58.0 g/mol.
