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2 years ago

Tungsten (W) and chlorine (Cl) form a series of compounds with the following compositions:_______.

Chemistry

1 answer:

deff fn [24]2 years ago

4 0

Answer:

WCl₂, WCl₄, WCl₅, WCl₆

Explanation:

Molar Mass of Tungsten = 184 g/mol

Mass of Chlorine = 35.5 g/mol

In the first compound;

Percentage of tungsten = 72.17 %

Upon solving;

72.17 % = 184

100 % = Total mass

Total mass of compound = 254.95g

Mass of chlorine = 254.95 - 184 = 70.95 (Dividing by 35.35; This is approximately 2 Chlorine atoms.

The Formular is WCl₂

In the second compound;

Percentage of tungsten = 56.45 %

Upon solving;

56.45 % = 184

100 % = Total mass

Total mass of compound = 325.95 g

Mass of chlorine = 325.95 - 184 = 141.95g (Dividing by 35.35; This is approximately 4 Chlorine atoms.

The Formular is WCl₄

In the third compound;

Percentage of tungsten = 50.91 %

Upon solving;

50.91 % = 184

100 % = Total mass

Total mass of compound = 361.42 g

Mass of chlorine = 361.42 - 184 = 177.42 (Dividing by 35.35; This is approximately 5 Chlorine atoms.

The Formular is WCl₅

In the fourth compound;

Percentage of tungsten = 46.39 %

Upon solving;

46.39 % = 184

100 % = Total mass

Total mass of compound = 396.64 g

Mass of chlorine = 396.64 - 184 = 212.64 (Dividing by 35.35; This is approximately 6 Chlorine atoms.

The Formular is WCl₆

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ikadub [295]

Answer:

74mL

Explanation:

Given parameters:

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Concentration of citric acid = 0.8M

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Unknown parameters:

Volume of citric acid = ?

Solution

Equation of the reaction:

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Procedure:

We work from the known parameters to the unknown. From the statement of the problem, we can approach the solution from the parameters of the baking powder.
From the baking powder, we can establish a molar relationship between the two reactants. We employ the mole concept in this regard.
We find the number of moles of the baking powder that went into the reaction using the expression below:

Number of moles = $\frac{mass}{molar mass}$

Number of moles = $\frac{15}{84}$ = 0.179mole

From the equation of the reaction, we can find the number of moles of the citric acid:

3 moles of baking powder reacted with 1 mole of citric acid

0.179 moles of baking powder would react with $\frac{0.179}{3}$ :

This yields 0.059mole of citric acid

To find the volume of the citric acid, we use the mole expression below:

Volume of citric acid = $\frac{number of moles}{concentration}$

Volume of citric acid = $\frac{0.059}{0.8}$ = 0.074L

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Answer:

Explanation:

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Explanation:

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Answer:

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