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2 years ago

HELP ME GUYS I NEED HELP RN

Chemistry

1 answer:

Tomtit [17]2 years ago

5 0

Answer:

Robot 1 : 150 J

Robot 2: 40 J

Explanation:

30 N x 5m = 150 J

20 N x 2m = 40 J

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During the chemical reaction given below 21.71 grams of each reagent were allowed to react. Determine how many grams of the exce

swat32

Answer: 16.32 g of $O_2$ as excess reagent are left.

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

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2 moles of $SO_2$ require = 1 mole of $O_2$

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Read 2 more answers

What is the number of moles in 15.0 g AsH3?

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We are given with the mass of Arsine ( $AsH_{3}$

The mass of arsine is 15g

there is a relation between moles, mass and molar mass of any compound which is

$moles=\frac{mass}{molarmass}$

The molar mass of Arsine = atomic mass of As + 3X atomic mass of H

the molar mass of Arsine = 74.92 + 3X 1 = 77.92 g/mol

Let us calculate the moles as

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