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2 years ago

Need help will give brainlest for correct answer and explanation.

Mathematics

1 answer:

solmaris [256]2 years ago

8 0

Answer:

Step-by-step explanation:

Because a function can only have one value of y for one value of x (see vertical line test) only A and D could be parts of the function.

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State the domain and the range of each relation. Then determine whether the relation is a function.

IrinaVladis [17]

Answer:

$Domain:$ { $-6,3,4$ }

$Range:$ { $-2,5,6,23$ }

The relation is not a function.

Step-by-step explanation:

By definition, a relation is a function if each input value has only one output value.

Given the relation:

(4,23)

(3,-2)

(-6,5)

(4,6)

The domain is the set of the x-coordinates of each ordered pair (You do not need to write 4 twice):

$Domain:$ { $-6,3,4$ }

The range is the set of the y-coordinates of each ordered pair :

$Range:$ { $-2,5,6,23$ }

Since the input value 4 has two different output values (23 and 6), the relation is not a function.

8 0

2 years ago

Read 2 more answers

Annie, Brianna & Carly are selling fruit boxes to raise money for their soccer team. All together the girls have sold 105 bo

GaryK [48]

Step-by-step explanation:

Annie = x

Brianna = y

Carly = z

Now,

x + y + z = 105 ...(1)

Carly has sold ten more than three times Brianna's sales.

z = 10 + 3y ...(2)

Brianna sold five more than Annie.

y = 5 + x ...(3)

Now,

z = 10 + 3y

z = 10 + 3(5 + x)

z = 10 + 15 + 3x

z = 25 + 3x

Now,

x + y + z = 105

x + (5 + x) + 25 + 3x = 105

5x + 30 = 105

5x = 105 - 30

5x = 75

5x/5 = 75/5

x = 15

So,

y = 5 + x

y = 5 + 15

y = 20

Now,

z = 25 + 3x

z = 25 + 3(15)

z = 25 + 45

z = 70

Thus,

Annie Sold 15 boxes

Brianna Sold 20 boxes

Carly Sold 70 boxes

6 0

1 year ago

What are the equations for these graphs

telo118 [61]

There are no graphs available.

4 0

2 years ago

If M is the midpoint of XY, find the coordinates of X if M(-3,-1) and Y(-8,6)

vova2212 [387]

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
X&({{ a}}\quad ,&{{ b}})\quad 
% (c,d)
Y&({{ -8}}\quad ,&{{ 6}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)$

$\bf \left( \cfrac{-8+a}{2}~,~\cfrac{6+b}{2} \right)=\stackrel{M}{(-3,-1)}\implies 
\begin{cases}
\cfrac{-8+a}{2}=-3\\\\
-8+a=-6\\
\boxed{a=2}\\
----------\\
\cfrac{6+b}{2}=-1\\\\
6+b=-2\\
\boxed{b=-8}
\end{cases}$

5 0

2 years ago

What is the simplest from of this expression? (-3x^2 + 4x) + (2x^2 - x -11)

mr Goodwill [35]

Answer:

Step-by-step explanation:

7 0

2 years ago