Answer:
<em>1500(1.02)^x + 600x</em> is how much he has in savings at the end of x years where it be in the bank or elsewhere
Step-by-step explanation:
x is in years
Let's just think about the investment of 1500 in an account earning 2% per year.
Before the years even start, you are at 1500 ( present value).
The next year (year 1), it would be 1500*.02+1500=(1500)(1.02).
The next year (year 2), it would be 1500(1.02)(.02)+1500(1.02)=1500(1.02)(1.02).
We keep multiplying factors of (1.02) each time.
So for year x, you would have saved 1500(1.02)^x.
Now we are saving 50 cash per month. Per year this would be 12(50) since there are 12 months in a year. 12(50)=600.
So the first year you would have 600.
The second year you would have 600(2) or 1200.
The third year you would have 600(3) or 1800.
Let's put this together:
1500(1.02)^x + 600x
There is not an answer to an expression.
-3+p is an expression, unless there was an equal sign and a sum at the end, that is when we can solve for the variable x.
-3+p simply equals -3+p
Answer:
angle M
horizontally in a positive
vertically in a positive
Answer:
C. The bottom answer.
Step-by-step explanation:
The value of the constant k when the value of x and y is 7 and 3 respectively in the equation xy=k is 21.
<h3>What is an equation?</h3>
An equation is formed when two equal expressions are equated together with the help of an equal sign '='.
The value of the constant k when the value of x and y is 7 and 3 respectively in the equation xy=k can be written as,
Hence, the value of the constant k when the value of x and y is 7 and 3 respectively in the equation xy=k is 21.
Learn more about Equation:
brainly.com/question/2263981
