Answer:
0.006 48 km/s
Explanation:
1. Convert miles to kilometres
14.5 mi × (1.609 km/1 mi) = 23.33 km
2. Convert hours to seconds
1 h × (60 min/1h) × (60 s/1 min) = 3600 s
3. Divide the distance by the time
14.5 mi/1 h = 23.3 km/3600 s = 0.006 48 km/s
D. It has almost no hydrogen ions, therefore it is very basic.
<span>First:
46.7 g of N with 53.3 g of O,
=> mass ratio O to N = 53.3 / 46.7 = 1.1413
Second
17.9 g of N and 82.0 g of O.
mass ratio of O to N = 82.0 / 17.9 = 4.5810
Third
Ratio of the mass ratio of O to N in the second compound
to the mass ratio of O to N in the first compound =
= 4.5810 / 1.1413 = 4.013 ≈ 4
Answer: 4
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Answer:
For the first ionization energy for an N2 molecule, the molecular orbital that the electron is removed from is the p orbital.
It should be noted that valence electrons simply refer to the electrons in an atom that holds the last orbital that is required for chemical bonding with other elements.
The existence of valence electrons can define the chemical properties of that atom. For the first energy in ionization of an N2 molecule, the molecular orbital where the electron could be extracted is the p orbital since it has the highest energy level.
Circumference of carbon and sulphur is 483.56 & 646.84 respectively