Answer:
48 π
Step-by-step explanation:
Area of Circle =πr∧2
Big Circle Area = π(8)∧2 = 64π
Small Circle Area =π(4)∧2= 16π
Shaded Region = 64π - 16π = 48π
No, since 0 doesn't belong to the domain.
What you need to do is give these problems a common denominator. Which makes 3/21 and14/21 respectively. Logically, you need to walk 4/21 of the trail. This can’t be simplified further.
The area of a dodecagon is 1/2aP
where:
a-apothem
P-perimeter
In the figure you will draw a point to any side and make a line perpendicular from a center to that side. Then if u think u can see that with only one draw of a hypotenuse can form a triangle. Then after drawing the hypotenuse which has 2 triangles, make the top angle of 1 triangle there are 30 degrees. On the down part is perpendicular and the left or the right is the 60 degrees. After that using special right triangles like the 30, 60, 90,. Then at the base of the one it bisected dived them by 2 for the 2 triangle's base. After that solve using it since the radius is 14. The apothem is 14(sqrt of 3). So after solving them the perimeter of each dodecagon is 12 sided so 14x12 is 168
A=1/2aP
A=1/2(14)(sqrt of 3)(168)
A=1176(sqrt of 3)
Thats the area of the dodecagon now the circle
A=(pi)r^2
A=(pi)(9)^2
A=81pi
Therefore the color purple is greater than the color green
