Answer:
ntergalactic space takes up most of the volume of the universe, but even galaxies and star systems consist almost entirely of empty space.
Explanation:
so to be exact galixes do make up most of the volume of space because galaxies are what make up space!
Im 70 percent sure that the right answer is chromosphere
Answer:
RE of Hydrogen = 6.47 x RE of Krypton
Explanation:
Actually the correct formula for comparing rate of effusion (RE) of two gases is:
RE of Gas A
------------------- = √ ( Molar mass of B / Molar mass of A)
RE of Gas B
You can designate which of the two gases you have (hydrogen and krypton) will be your gas A and gas B. So for this particular problem, let us make hydrogen as gas A and Krypton as gas B. So the equation becomes:
RE of Hydrogen
------------------------- = √ (Molar mass of Krypton / Molar mass of Hydrogen)
RE of Krypton
Get the molar masses of Hydrogen and Krypton in the periodi table:
RE of Hydrogen
------------------------- = √ (83.798 g/mol / 2 g/mol)
RE of Krypton
RE of Hydrogen
------------------------- = 6.47 ====> this can also be written as:
RE of Krypton
RE of Hydrogen = 6.47 x RE of Krypton
It means that the rate of effusion of Hydrogen gas will be 6.47 faster than the rate of effusion of Krypton gas. With the type of question you have, it doesn't matter which gases goes on your numerator and denominator. What's important is that you show the rate of effusion of a gas with respect to the other. But if that's concerns you the most, then take the gas which was stated first as your gas A and the latter as your gas B unless the problem tells you which one will be on top and which is in the bottom.
Answer:
Wave frequency can be measured by counting the number of crests (high points) of waves that pass the fixed point in 1 second or some other time period. The higher the number is, the greater the frequency of the waves. ... For example, it is the distance between two adjacent crests in the transverse waves in the diagram.
Explanation:
Answer and Explanation:
It is given that bulb A has the half the resistance as B
WHEN THEY ARE CONNECTED IN SERIES : In series circuit we know that current is same in the whole circuit
The power is given by 
the expression it is clear that the bulb which has more resistance consume more power as current is same, and the bulb which consume more power will be brightest
It is given that resistance of bulb A is half the resistance of B So bulb A will be dimmest in this case
WHEN THEY ARE CONNECTED IN PARALLEL : In parallel circuit voltage is same across the circuit
The power is given by 
from the expression it is clear that the bulb which has least resistance will consume more power and so will be brightest
As the resistance of bulb A is less so it will be brightest in this case
