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2 years ago

Find the ratio of effusion rates of hydrogen gas and krypton gas.

Physics

1 answer:

algol132 years ago

3 0

Answer:

RE of Hydrogen = 6.47 x RE of Krypton

Explanation:

Actually the correct formula for comparing rate of effusion (RE) of two gases is:

RE of Gas A

------------------- = √ ( Molar mass of B / Molar mass of A)

RE of Gas B

You can designate which of the two gases you have (hydrogen and krypton) will be your gas A and gas B. So for this particular problem, let us make hydrogen as gas A and Krypton as gas B. So the equation becomes:

RE of Hydrogen

------------------------- = √ (Molar mass of Krypton / Molar mass of Hydrogen)

RE of Krypton

Get the molar masses of Hydrogen and Krypton in the periodi table:

RE of Hydrogen

------------------------- = √ (83.798 g/mol / 2 g/mol)

RE of Krypton

RE of Hydrogen

------------------------- = 6.47 ====> this can also be written as:

RE of Krypton

RE of Hydrogen = 6.47 x RE of Krypton

It means that the rate of effusion of Hydrogen gas will be 6.47 faster than the rate of effusion of Krypton gas. With the type of question you have, it doesn't matter which gases goes on your numerator and denominator. What's important is that you show the rate of effusion of a gas with respect to the other. But if that's concerns you the most, then take the gas which was stated first as your gas A and the latter as your gas B unless the problem tells you which one will be on top and which is in the bottom.

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An object is made of glass and has the shape of a cube 0.13 m on a side, according to an observer at rest relative to it. Howeve

Vlad1618 [11]

Answer:

$v=0.9833\ c$

Explanation:

The density changes means that the length in the direction of the motion is changed.

Therefore,

$\text{Density} = \frac{m}{lwh}$

Given :

Side, b = h = 0.13 m

Mass, m = 3.3 kg

Density = 8100 $kg/m^3$

So,

$8100=\frac{3.3}{l \times 0.13 \times 0.13}$

$l=\frac{3.3}{8100 \times 0.13 \times 0.13}$

l = 0.024 m

Then for relativistic length contraction,

$l= l' \sqrt{1-\frac{v^2}{c^2}}$

$0.024= 0.13 \sqrt{1-\frac{v^2}{c^2}}$

$0.184= \sqrt{1-\frac{v^2}{c^2}}$

$0.033= 1-\frac{v^2}{c^2}}$

$\frac{v^2}{c^2}= 0.967$

$\frac{v}{c}=0.9833$

$v=0.9833\ c$

Therefore, the speed of the observer relative to the cube is 0.9833 c (in the units of c).

3 0

2 years ago

Saturn has an orbital period of 29.46 years. In two or more complete sentences, explain how to calculate the average distance fr

bixtya [17]

For astronomical objects, the time period can be calculated using:
T² = (4π²a³)/GM
where T is time in Earth years, a is distance in Astronomical units, M is solar mass (1 for the sun)
Thus,
T² = a³
a = ∛(29.46²)
a = 0.67 AU
1 AU = 1.496 × 10⁸ Km
0.67 * 1.496 × 10⁸ Km
= 1.43 × 10⁹ Km

8 0

2 years ago

Variables in physics often include a subscript. What are subscripts used for in physics?

Viefleur [7K]

Answer:

C.) To indicate different versions of the same variable.

Explanation:

Variables in physics often include a subscript. These subscripts are used for indicating different versions of the same variable in physics.

Basically, subscripts are used to represent the beginning (initial) and ending (final) position or point of a variable in physics.

For example, we would look at Gay Lussac' Law of gases.

Gay Lussac law states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Gay Lussac's law is given by;

$PT = K$

$\frac{P1}{T1} = \frac{P_{2}}{T_{2}}$

Where;

$T_{1}$ represents the initial temperature.

$T_{2}$ represents the initial temperature.

$P_{1}$ represents the initial pressure.

$P_{2}$ represents the initial pressure.

Note: 1 and 2 are the subscript while T and P are the variables.

4 0

2 years ago

24 grams of magnesium metal reacts with 16 grams of oxygen gas to form magnesium oxide. according to the law of conservation of

wariber [46]

The mass of magnesium oxide must be 40 grams

Explanation:

The law of conservation of mass states that the total mass of the reactant in a chemical reaction must be equal to the total mass of the products after the reaction has completed.

In this problem, we have:

Reactants:

Magnesium metal (mass: 24 grams)

Oxygen gas (mass: 16 grams)

Products:

Magnesium oxide (mass: ?)

According to the law of conservation of mass, the mass of the magnesium oxide must be equal to the sum of the mass of the magnesium metal and the oxygen gass. Therefore:

Mass (magnesium oxide) = 24 g + 16 g = 40 g

Learn more about law of conservation of mass:

brainly.com/question/5017646

#LearnwithBrainly

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2 years ago

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kari74 [83]

Answer:

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Explanation:

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