Ask question

Ask question

All categories

2 years ago

15

Find the area of a parallelogram with a base of 5 cm and a height of 15 cm.

1 answer:

amid [387]2 years ago

4 0

Answer:

75cm²

Step-by-step explanation:

area of parallelogram= base*height

area=15*5=75cm²

You might be interested in

<img src="https://tex.z-dn.net/?f=%20%28%7B%20%7Bx%7D%5E%7B2%7D%20%20-%204%7D%29%5E%7B5%7D%20%28%20%7B4x%20-%205%7D%29%5E%7B4%7D

Makovka662 [10]

Let $u=x^2-4$ and $v=4x-5$ . By the product rule,

$\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}$

By the power rule, we have $(u^5)'=5u^4$ and $(v^4)'=4v^3$ , but $u,v$ are functions of $x$ , so we also need to apply the chain rule:

$\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}$

$\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}$

and we have

$\dfrac{\mathrm du}{\mathrm dx}=2x$

$\dfrac{\mathrm dv}{\mathrm dx}=4$

So we end up with

$\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3$

Replace $u,v$ to get everything in terms of $x$ :

$\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3$

We can simplify this by factoring:

$10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3=2(x^2-4)^4(4x-5)^3\bigg(5x(4x-5)+8(x^2-4)\bigg)$

$=2(x^2-4)^4(4x-5)^3(28x^2-57)$

7 0

2 years ago

The sum of two numbers is 64 and the difference is 6. What are the numbers?

Ne4ueva [31]

Answer:

29 and 35

Step-by-step explanation:

x+y=64

x-y=6

Solve by substitution.

x=6+y

6+y+y=64

6+2y=64

y=29

Then plug in 29 for y.

x+29=64 ......35

7 0

2 years ago

What are these two questions please help

Kay [80]

15 feet is what I came up with.

3 0

2 years ago

Lulu has exactly enough fencing to go around her rectangular garden. She has 40 m of fencing and the garden is 8 m wide. What is

vesna_86 [32]

Answer:12 m

Step-by-step explanation:

Given

Width of garden $W=8\ m$

Total fencing $T=40\ m$

If Lulu has enough fencing to go around her rectangular garden then , it should be equal to perimeter of garden

Suppose L is the length of garden

Therefore perimeter is $P=2(L+W)$

$2(L+W)=40$

$L+W=20$

$L=20-8=12\ m$

thus length of fencing is $12\ m$

4 0

3 years ago

Which number has the smallest value

tester [92]

Answer:

c would be the correct answer

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers