Answer:
B. 3/4
Step-by-step explanation:
I just did it and got it right
The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
Let w represent the width, hence:
length = w + 33, height = w - 13
Volume (V) = w(w + 33)(w - 13) = w³ + 20w² - 429w
V(w) = w³ + 20w² - 429w
Rate of change = dV/dw = 3w² + 40w - 429
When w = 38, dV/dw = 3(38)² + 40(38) - 429 = 5423
When w = 53, dV/dw = 3(53)² + 40(53) - 429 = 10118
Rate = 10118 - 5423 = 4695 in³/in
The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
Find out more on equation at: brainly.com/question/2972832
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Answer:
The equation of line with given points and perpendicular to y-axis is
y = - 7
Step-by-step explanation:
Given as :
The given points as ( - 10 , - 7)
The equation of line is Y = mX + c
So The line will satisfy given points
Or, - 7 = m ( -10 ) + c
Now This line is perpendicular to y- axis
∴ The slop of line perpendicular to y axis is 0
So, - 7= 0 + c
or, c = - 7
∴ Equation of line is y = 0 + c
Or, y = - 7
Hence The equation of line with given points and perpendicular to y-axis is y = - 7 Answer
Answer:
60.9
Step-by-step explanation: