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2 years ago

£3000 is invested at 4% compound interest per annum. What is the value of the investment after 3 years?

Mathematics

1 answer:

djverab [1.8K]2 years ago

4 0

£3000 x 0.4 to the power of 3= £192
£192 + £3000 = £3192

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Ann Zoe and Jim bought a present for ben. Ann cooperated with $12 less than Zoe and $16 less than Jim. If the cost of the presen

sergeinik [125]

Let A represent the amount Ann contributed, Z represent Zoe's contribution, and J represent Jim's contribution toward the present.

Ann (A): A

Zoe (Z): A = Z - 12 → Z = 12 + A

Jim (J): A = J - 16 → J = 16 + A

A + Z + J = 154

(A) + (12 + A) + (16 + A) = 154

3A + 28 = 154

3A = 126

A = 42

Ann (A): A = 42

Zoe (Z): Z = 12 + A = 12 + 42 = 54

Jim (J): J = 16 + A = 16 + 42 = 58

Answer: Ann=42, Zoe=54, Jim=58

6 0

2 years ago

Predict if the product will be greater than, less than or equal to the second factor 4/5 x 1 2/5 = y

Radda [10]

Answer:

The product will be less than the second factor.

Step-by-step explanation:

Given the expression

$\frac{4}{5}\:\times \:1\frac{2}{5}\:=y$

solving to determine the product value

$y=\:\frac{4}{5}\times \:\:1\frac{2}{5}$

$=\frac{4}{5}\times \frac{7}{5}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}$

$=\frac{4\times \:7}{5\times \:5}$

$=\frac{28}{5\times \:5}$

$=\frac{28}{25}$

As the value of the second factor is:

$1\frac{2}{5}=\frac{7}{5}=1.4$

And the product value is:

$y=\frac{28}{25}=1.12$

It is clear that the product value 'y = 1.12' is lesser than the second factor value '1.4'.

i.e. 1.12 < 1.4

Thus, the product will be less than the second factor.

4 0

2 years ago

Please help!!!

stiv31 [10]

Answer:

Step-by-step explanation:

1. Percent means out of 100

8% = 8/100

.08

2. Is means equals and of means multiply

W = 48% *180

W = .48 *180

W =86.4

3. Is means equals and of means multiply

80 = 125% * W

80 = 1.25 W

Divide each side by 1.25

80/1.25 = W

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2 years ago

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