Answer:
a. 0.12109
b. 0.0001668
c .0.9726
d. 0.01038
e. 0.01211
f. 0.000001731
Step-by-step explanation:
Sample size = 580
Defective units = 8
Number of picks = 2
a) If the first container is defective, there 7 defective containers left in a population of 579. The probability of selecting a defective one is:
b) The probability that both are defective is given by:
c) The probability that both are acceptable is given by:
d) In this case, two defective units were removed from the batch, the probability that the third is also defective is:
e) In this case, one acceptable and one defective unit were removed from the batch, the probability that the third is also defective is:
f) The probability that all three are defective is given by:
If both the hoses are on the same time then the height of the water in the pool is given by the expression 15g^2 + 5g - 6
Step-by-step explanation:
(7g^2 + 3g - 4) + (8g^2 + 2g - 2)
= (7g^2 + 8g^2) + ( 3g + 2g) + (-4 -2)
with the help of distribution law,
= (7 +8)g^2 + (3 + 2)g - (4 + 2)
= 15g^2 + 5g - 6
Therefore if both the hoses are on the same time then the height of the water in the pool is given by the expression 15g^2 + 5g - 6
Answer: i believe that it is 49 hits
Comment:
and believe me sis i feel ya i'm in 8th grade and fell behind tryna help other people because i don't want others to feel what i felt.
GOOD LUCK!
Easy example that shows
:
Let
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Then
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So
, or
, and so
.
The basic idea is to find the period of the repeating decimal, move the
digits belonging to one period over to the left of the decimal point by multiplying by
, then subtract the original repeating decimal from this new number, and finally divide by
.
A slightly more complicated example:
Let
.
Then
.
Then
, or