3. What is found around the roots of some plants that turns nitrogen from the form we cannot use to the form we can use?

Chemistry

1 answer:

dsp732 years ago

5 0

Answer:

Bacteria

Explanation:

Some plants, specifically leguminous plants form a symbiotic relationship with certain bacteria species called NITROGEN-FIXING BACTERIA in their root nodules. In this relationship, the bacteria species e.g nitrosomonas, nitrobacter etc help the plants fix atmospheric nitrogen (N2) or ammonium compounds, which are forms of nitrogen that are unusable to the plant into nitrates, a usable form.

Therefore, BACTERIA are the organisms found around the roots of these set of plants (legumes) that turns nitrogen from the form we cannot use to the form we can use.

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Whitepunk [10]

To determine which order of the reaction it is, first we need to calculate the rate of change of moles.
the data is as follows
time 0 40 80 120 160
moles 0.100 0.067 0.045 0.030 0.020

Q1)
for the first 40 s change of moles ;
= -d[A] / t
= - (0.067-0.100)/40s
= 8.25 x 10⁻⁴ mol/s
for the next 40 s
= -(0.045-0.067)/40
= 5.5 x 10⁻⁴ mol/s
the 40 s after that
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and A is the only reactant that affects the rate of the reaction

rate = k [A]ᵇ
8.25 × 10⁻⁴ mol/s = k [0.100 mol]ᵇ ----1
5.5 x 10⁻⁴ mol/s = k [0.067 mol]ᵇ -----2
divide the 2nd equation by the 1st equation
1.5 = [1.49]ᵇ
b is almost equal to 1
Therefore this is a first order reaction

Q2)
to find out the rate constant(k), we have to first state the equation for a first order reaction.
rate = k[A]ᵇ
As A is the only reactant thats considered for the rate equation.
Since this is a first order reaction,
b = 1
therefore the reaction is
rate = k[A]
substituting the values,
8.25 x 10⁻⁴ mol/s = k [0.100 mol]
k = 8.25 x 10⁻⁴ mol/s /0.100mol
= 8.25 x 10⁻³ s⁻¹

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Deffense [45]

Answer:

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Explanation:

[OH-] = 10^-pOH, so

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