If you are given 96.0 grams of O2, how many grams of H20 are made?
1 answer:
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Answer:
Final pressure in (atm) (P1) = 6.642 atm
Explanation:
Given:
Initial volume of gas (V) = 12.5 L
Pressure (P) = 784 torr
Temperature (T) = 295 K
Final volume (V1) = 2.04 L
Final temperature (T1) = 310 K
Find:
Final pressure in (atm) (P1) = ?
Computation:
According to combine gas law method:
⇒ Final pressure (P1) = 5,048.18877 torr
⇒ Final pressure in (atm) (P1) = 5,048.18877 torr / 760
⇒ Final pressure in (atm) (P1) = 6.642 atm