Ok sure! Let's start with the marbles first. We have one red one blue and one green. There is a red and a blue cube. All we do is list the possible combinations of one marble and one cube. The answer would be : 1 blue marble, 1 blue cube. 1 red marble, 1 blue cube. 1 green marble, 1 blue cube. Then again but with the red cube. So in all, there are 6 possible combinations. Hope this helps. ☺️
Kx-3y=k
y=4x+1 ( we will put it in 1st equation )
kx - 3 (4x+1)=k
kx - 12 x - 3 =k
kx - 12 x = k+3
x(k-12) = k+3
x=
Also y=
We can not divide with zero.
k-12=0
k=12For k= 12 equations have no solutions.
Yeah yeah but yeah i is going camping on the golf thing and he said he has no idea where y’all
Answer: Look for key words.
Step-by-step explanation:
Example: 15 added and 24.
Added is the key word
24 + 15
Answer:
6. xint=-7
yint=-3
7. xint=-7
yint=-5
Step-by-step explanation: