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2 years ago

I need help on how to do combinations

Mathematics

1 answer:

Veronika [31]2 years ago

3 0

Ok sure! Let's start with the marbles first. We have one red one blue and one green. There is a red and a blue cube. All we do is list the possible combinations of one marble and one cube. The answer would be : 1 blue marble, 1 blue cube. 1 red marble, 1 blue cube. 1 green marble, 1 blue cube. Then again but with the red cube. So in all, there are 6 possible combinations. Hope this helps. ☺️

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Find all the solutions to the equation 7sin^2x -14sinx+2=-5

Allisa [31]

I will get you started.

Let sin x = u

Then 7sin^2x -14sinx+2=-5 become

7u^2 - 14u = - 5

7u^2 - 14u + 5 = 0

Steps:

1. Solve for u.

2. Back- substitute for u.

3. Take the arcsin on both sides to find the angle(s).

You finish.

7 0

2 years ago

Points that do not lie in the same plane are called________points

rodikova [14]

Answer:

non - collinear points

Step-by-step explanation:

points that dont lie on the same line

3 0

2 years ago

Which of the following is the solution to |7x+12|=12

tamaranim1 [39]

Answer:

$x=-\frac{24}{7}\\x=0$

Step-by-step explanation:

1. You must clear the absolute value bars.

2. You have two cases: a positive case and a negative case.

3. First, you can solve the positive case as following:

$7x+12=12\\7x=12-12\\x=0$

4. Now, you must solve thie negative case as you can see below:

$-(7x+12)=12\\-7x-12=12\\-7x=24\\x=-\frac{24}{7}$

5. Therefore, the answer is:

$x=-\frac{24}{7}\\x=0$

6 0

2 years ago

Help me with question a please ! With full workings !

frosja888 [35]

A)

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
% (c,d)
P&({{ 0.5}}\quad ,&{{ 0}})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}$

$\bf QP=\sqrt{(0.5-0)^2+(0-2)^2}\implies QP=\sqrt{0.5^2+2^2}
\\\\\\
QP=\sqrt{\left( \frac{1}{2} \right)^2+4}\implies QP=\sqrt{ \frac{1^2}{2^2}+4}\implies QP=\sqrt{\frac{1}{4}+4}
\\\\\\
QP=\sqrt{\frac{17}{4}}\implies QP=\cfrac{\sqrt{17}}{\sqrt{4}}\implies QP=\cfrac{\sqrt{17}}{2}$

b)

since QR=QP, that means that QO is an angle bisector, and thus the segments it makes at the bottom of RO and OP, are also equal, thus RO=OP

thus, since the point P is 0.5 units away from the 0, point R is also 0.5 units away from 0 as well, however, is on the negative side, thus R (-0.5, 0)

c)

what's the equation of a line that passes through the points (-0.5, 0) and (0,2)?

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
% (c,d)
R&({{ -0.5}}\quad ,&{{ 0}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{0-2}{-0.5-0}\implies \cfrac{-2}{-0.5}$

$\bf m=\cfrac{\frac{-2}{1}}{-\frac{1}{2}}\implies \cfrac{-2}{1}\cdot \cfrac{2}{-1}\implies 4
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-2=4(x-0)\implies y=4x+2\\
\left. \qquad \right. \uparrow\\
\textit{point-slope form}$

7 0

2 years ago

I have 3 questions for math

Airida [17]

Answer:

no question content
(x, y) = (1/2, 4)
(x, y) = (2, 10)

Step-by-step explanation:

1. No link, no question

2. Divide the first equation by 2 and substitute for y using the expression in the second equation.

2x +(4x+2) = 5

6x = 3 . . . . . . . . . subtract 2

x = 3/6 = 1/2 . . . . divide by2

y = 4(1/2) +2 = 4 . . . . substitute into the equation for y

The solution is (x, y) = (1/2, 4).

3. The solution using a graphing calculator is (x, y) = (2, 10). (see attached)

7 0

2 years ago