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2 years ago

Identify the y-intercept of the graph of 3x + y = 6

Mathematics

1 answer:

Gelneren [198K]2 years ago

8 0

Answer:

The x-intercept is the place where the line crosses the x-axis. In other words, y=0. The y-intercept is (0,6).

Step-by-step explanation:

3x+y=6

3(0)+y=6

0+y=6

y=6

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Lynne invested 35,000 into an account earning 4% annual interest compounded quarterly she makes no other deposits into the accou

storchak [24]

Hello!

Lynne invested 35,000 into an account earning 4% annual interest compounded quarterly she makes no other deposits into the account and does not withdraw any money. What is the balance of Lynne's account in 5years

Data:

P = 35000

r = 4% = 0,04

n = 4

t = 5

P' = ?

I = ?

We have the following compound interest formula

$P' = P*(1+\dfrac{r}{n})^{nt}$

$P' = 35000*(1+\frac{0,04}{4})^{4*5}$

$P' = 35000*(1+0,01)^{20}$

$P' = 35000*(1,01)^{20}$

$P' = 35000*(1.22019003995...)$

$P' \approx 42,706.66$

So the new principal P' after 5 years is approximately $42,706.66.

Subtracting the original principal from this amount gives the amount of interest received:

$P' - P = I$

$42,706.66 - 35000 = \boxed{\boxed{7,706.66}}\end{array}}\qquad\checkmark$

________________________

I Hope this helps, greetings ... Dexteright02! =)

4 0

2 years ago

Solve the equation using the distributive property and properties of equality. 1/2(x+6)=18 What is the value of x?

fgiga [73]

If what you mean is what does x equal then X=30

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2 years ago

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Find sinϴ and cosϴ if tanϴ=1/4 and sinϴ>0

eduard

If you're using the app, try seeing this answer through your browser: brainly.com/question/2787701

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$\mathsf{tan\,\theta=\dfrac{1}{4}\qquad\qquad(sin\,\theta\ \textgreater \ 0)}\\\\\\
\mathsf{\dfrac{sin\,\theta}{cos\,\theta}=\dfrac{1}{4}}\\\\\\
\mathsf{4\,sin\,\theta=cos\,\theta\qquad\quad(i)}$

Square both sides:

$\mathsf{(4\,sin\,\theta)^2=(cos\,\theta)^2}\\\\
\mathsf{4^2\,sin^2\,\theta=cos^2\,\theta}\\\\
\mathsf{16\,sin^2\,\theta=cos^2\,\theta\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\
\mathsf{16\,sin^2\,\theta=1-sin^2\,\theta}$

$\mathsf{16\,sin^2\,\theta+sin^2\,\theta=1}\\\\
\mathsf{17\,sin^2\,\theta=1}\\\\
\mathsf{sin^2\,\theta=\dfrac{1}{17}}\\\\\\
\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{1}{17}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\dfrac{1}{\sqrt{17}}}$

Since $\mathsf{sin\,\theta}$ is positive, you can discard the negative sign. So,

$\mathsf{sin\,\theta=\dfrac{1}{\sqrt{17}}\qquad\quad\checkmark}$

Substitute this value back into $\mathsf{(i)}$ to find $\mathsf{cos\,\theta:}$

$\mathsf{4\cdot \dfrac{1}{\sqrt{17}}=cos\,\theta}\\\\\\
\mathsf{cos\,\theta=\dfrac{4}{\sqrt{17}}\qquad\quad\checkmark}$

I hope this helps. =)

Tags: <em>trigonometric identity relation trig sine cosine tangent sin cos tan trigonometry precalculus</em>

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2 years ago

Y = –x + 4<br> x + 2y = –8

valkas [14]

X=16
y= -12

X+2( -x+4)=-8
X-2x+8=-8
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X=16

Y=-16+4
Y=-12

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Given the following system of equations, what is the value of the y-coordinate of the solution?

Alina [70]

9/4 is the answer if you have any questions please let me know

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