All categories

2 years ago

What are the real or imaginary solutions of the polynomial x^3=9x

Mathematics

1 answer:

dem82 [27]2 years ago

8 0

Hello from MrBillDoesMath!

Answer:

x = 0, +\-3

Discussion:

x^3 = 9x => subtract 9x from both sides

x^3 - 9x = 0 => factor x from both terms

x(x^2-9) = 0 => x = 0 or x^2 - 9 = 0

x = 0, +\-3

Thank you,

MrB

You might be interested in

X=2y+11 <br> -7x-27=-13<br> solve with substitution

Lilit [14]

Answer:

x=13/7, y=-32/7

Step-by-step explanation:

Just trust me

8 0

2 years ago

Which of the following statements is true?

mash [69]

Answer:

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

The equation y - 2 = 3(x + 1) is in point-slope

attashe74 [19]

Y-2=3x+3
Then add two
So y=3x+5
Hope this helps sorry if wrong

5 0

3 years ago

The playing life of a Sunshine radio is normally distributed with mean LaTeX: \muμ = 600 hours and standard deviation LaTeX: \si

Hitman42 [59]

Answer:

The probability that a radio selected at random will last from 600 to 700 hours is 0.3413

Step-by-step explanation:

The playing life of a Sunshine radio is normally distributed

Mean = $\mu = 600 hours$

Standard deviation = $\sigma = 100 hours$

We are supposed to find the probability that a radio selected at random will last from 600 to 700 hours i.e.P(600<x<700)

Formula: $Z= \frac{x-\mu}{\sigma}$

At x = 600

$Z= \frac{600-600}{100}$

Z=0

$P(X$

At x = 700

$Z= \frac{700-600}{100}$

Z=1

$P(X$

$P(600$

Hence the probability that a radio selected at random will last from 600 to 700 hours is 0.3413

8 0

2 years ago

Round to 0, 1/2, or 1<br><br> 12/15 rounds to

Korvikt [17]

Question is confusing but 12/15 divides to 4/5 or rounds to 1

8 0

2 years ago

Read 2 more answers

What are the real or imaginary solutions of the polynomial x^3=9x​

What are the real or imaginary solutions of the polynomial x^3=9x