9514 1404 393
Answer:
- maximum: 15∛5 ≈ 25.6496392002
- minimum: 0
Step-by-step explanation:
The minimum will be found at the ends of the interval, where f(t) = 0.
The maximum is found in the middle of the interval, where f'(t) = 0.
![f(t)=\sqrt[3]{t}(20-t)\\\\f'(t)=\dfrac{20-t}{3\sqrt[3]{t^2}}-\sqrt[3]{t}=\sqrt[3]{t}\left(\dfrac{4(5-t)}{3t}\right)](https://tex.z-dn.net/?f=f%28t%29%3D%5Csqrt%5B3%5D%7Bt%7D%2820-t%29%5C%5C%5C%5Cf%27%28t%29%3D%5Cdfrac%7B20-t%7D%7B3%5Csqrt%5B3%5D%7Bt%5E2%7D%7D-%5Csqrt%5B3%5D%7Bt%7D%3D%5Csqrt%5B3%5D%7Bt%7D%5Cleft%28%5Cdfrac%7B4%285-t%29%7D%7B3t%7D%5Cright%29)
This derivative is zero when the numerator is zero, at t=5. The function is a maximum at that point. The value there is ...
f(5) = (∛5)(20-5) = 15∛5
The absolute maximum on the interval is 15∛5 at t=5.
39/6= 6.5 then u multiply
6.5 times 4 = 26
which 26 is your answer
A central angle in a circle with a radius of 7in. intercepts an arc with a length of 9in. What is the radian measure of the central angle?
Answer:
The correct answer is b.
Step-by-step explanation:
The wave equation is given generally as:
c(x, t) = Acos(kx - wt)
Where A = amplitude
k = wave number
w = angular frequency.
x = horizontal distance moves by the wave.
t = time
The options show to us that the wave depends only on t and not (x, t).
Hence, the wave equation becomes:
c(t) = Acos(wt)
Given that:
A = 5 V
f = 1 * 10⁶ Hz
Angular Frequency, w, is given as:
w = 2πf
w = 2 * π * 1 * 10⁶ Hz
w = 2π(1 * 10⁶)
The wave equation becomes:
c(t) = 5cos(2*π*1*10⁶)
The correct answer is b.
