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2 years ago

Please help me idk if I did it right

Mathematics

1 answer:

Oxana [17]2 years ago

5 0

1. The company replaces one-third of its fleet every year.

The fleet consists of 75 cars.

One-third of 75 is 75 / 3 = 25.

So, it replaces 25 cars every year.

2. In terms of full games, he gets (9 games) of playing time.

Explanation: He starts 12 games. He gets 3/4 of each game. So, 12*3/4=9

3. Jack grows vegetables on 4/3 acre. Sam grows vegetable on 5/4 acre. Which is bigger, 4/3 or 5/4?

4/3 is bigger.

So, Jack has the biggest area of vegetables.

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In a recent snail race, a snail traveled a distance of 1 1/6 inches in 2 minutes. Find the number if inches traveled per minute

Alecsey [184]

Answer:

For inch/min =0.9167 inch/min

For min/inch = 1.0908 min/inch

Step-by-step explanation:

The snail in the race traveled 11/6 inches in 2 minutes.

The number of inches per minute is equal to = (11/6)/(2)

= 11/12

=0.9167 inch/min

The number of minutes per inch is equal to = 1/(inch per min)

= 1/0.9167

= 1.0908 min/inch

Minutes per inch is gotten by taking the inverse of inch/min or dividing the number of minutes by number of inches

6 0

2 years ago

What is the midpoint of the segment below?

Veronika [31]

I am pretty sure it is B.

3 0

2 years ago

Assume that the following data were generated using a valid and appropriate methodology. XYZ Data Analytics, Inc. Received prope

Hitman42 [59]

Using the z-distribution, as we are working with a proportion, the 95% confidence interval for the proportion of consumers who would buy the product at it's proposed price is (0.3016, 0.3830).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.

179 out of 523 members indicated they would buy the new product at the proposed price, hence:

$\pi = \frac{179}{523} = 0.3423$

Then the bounds of the interval are found as follows:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3423 - 1.96\sqrt{\frac{0.3423(0.6577)}{523}} = 0.3016$

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3423 + 1.96\sqrt{\frac{0.3423(0.6577)}{523}} = 0.3830$

More can be learned about the z-distribution at brainly.com/question/25890103

4 0

1 year ago

A marketing firm randomly sends a mass promotional mailing to 21 %of the households in a new market area. From experience the fi

coldgirl [10]

Let X be the number of households.

so they sent the promotional material to 21% which means 0.21X number of households get the material.

out of the 0.21x households only 0.14 respond which is

0.14(0.21x) = 0.0294x or 2.94%

2.94% is the probability that a household receives and responds.

5 0

2 years ago

How do you solve 11+6(x+5)=42/ 9

kvasek [131]

First do the solving you CAN do

17(x+5)=4.67

then, get x by itself my moving 5 and 17 over

(17(x+5)/17=4.67/17

x+5=.<span>2745

x=-</span><span>4.725

and there's the answer!</span>

5 0

2 years ago