Answer:
The x-component of the electric field at the origin = -11.74 N/C.
The y-component of the electric field at the origin = 97.41 N/C.
Explanation:
<u>Given:</u>
- Charge on first charged particle,
- Charge on the second charged particle,
- Position of the first charge =
- Position of the second charge =
The electric field at a point due to a charge at a point distance away is given by
where,
- = Coulomb's constant, having value
- = position vector of the point where the electric field is to be found with respect to the position of the charge .
- = unit vector along .
The electric field at the origin due to first charge is given by
is the position vector of the origin with respect to the position of the first charge.
Assuming, are the units vectors along x and y axes respectively.
Using these values,
The electric field at the origin due to the second charge is given by
is the position vector of the origin with respect to the position of the second charge.
Using these values,
The net electric field at the origin due to both the charges is given by
Thus,
x-component of the electric field at the origin = -11.74 N/C.
y-component of the electric field at the origin = 97.41 N/C.
I believe the answer is "When a neutral atom looses an electron to another neutral atom, two charged atoms are created."
Answer:
The total resistance in a parallel circuit is always less than any of the branch resistances. Adding more parallel resistances to the paths causes the total resistance in the circuit to decrease. As you add more and more branches to the circuit the total current will increase because Ohm's Law states that the lower the resistance, the higher the current.
Explanation:
Directly proportional to pressure
Answer:
A. I = V / R = 12 / 252 = .048 amps
V = I * R = .048 * 252 = 12 V
V is also the reading the voltage across the battery (12 Volts)