Answer:
- 30/91
Step-by-step explanation:
Supposing a normal distribution, we find that:
The diameter of the smallest tree that is an outlier is of 16.36 inches.
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We suppose that tree diameters are normally distributed with <u>mean 8.8 inches and standard deviation 2.8 inches.</u>
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In a normal distribution with mean and standard deviation , the z-score of a measure X is given by:
- The Z-score measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.<u>
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In this problem:
- Mean of 8.8 inches, thus .
- Standard deviation of 2.8 inches, thus .
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The interquartile range(IQR) is the difference between the 75th and the 25th percentile.
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25th percentile:
- X when Z has a p-value of 0.25, so X when Z = -0.675.
75th percentile:
- X when Z has a p-value of 0.75, so X when Z = 0.675.
The IQR is:
What is the diameter, in inches, of the smallest tree that is an outlier?
- The diameter is <u>1.5IQR above the 75th percentile</u>, thus:
The diameter of the smallest tree that is an outlier is of 16.36 inches.
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A similar problem is given at brainly.com/question/15683591
The height of the given trapezoid is 7.5 m.
Step-by-step explanation:
Step 1:
The trapezoid's area is calculated by averaging the base lengths and multiplying it with the trapezoid's height.
The trapezoid's area,
Here is the lower base length and is the upper base length while h is the height.
Step 2:
In the given problem, and . Assume the height is h m.
The trapezoid's area
So the height of the given trapezoid is 7.5 m.
Answer:
11*pi/36
Step-by-step explanation:
Answer:
Step-by-step explanation:
Can u plz write it i cant see the pic