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2 years ago

Experts please please PLEASE answer this question ASAP! Due today.

Mathematics

1 answer:

quester [9]2 years ago

8 0

The height of the given trapezoid is 7.5 m.

Step-by-step explanation:

Step 1:

The trapezoid's area is calculated by averaging the base lengths and multiplying it with the trapezoid's height.

The trapezoid's area, $A = \frac{b_{1}+b_{2}}{2} (h).$

Here $b_{1}$ is the lower base length and $b_{2}$ is the upper base length while h is the height.

Step 2:

In the given problem, $b_{1}=5 \mathrm{m}$ and $b_{2}=3 \mathrm{m}$ . Assume the height is h m.

The trapezoid's area $= 30.$

$30 = \frac{5+3}{2} (h), 30 = (4)(h).$

$h = \frac{30}{4} = 7.5.$

So the height of the given trapezoid is 7.5 m.

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An airplane travels 6111 kilometers against the wind in 9 hours and 7911 kilometers with the wind in the same amount of time. Wh

natima [27]

Answer:

Speed of the plane in still air: $779\; {\rm km \cdot h^{-1}}$ .

Windspeed: $100\; {\rm km \cdot h^{-1}}$ .

Step-by-step explanation:

Assume that $x\; {\rm km \cdot h^{-1}}$ is the speed of the plane in still air, and that $y\; {\rm km \cdot h^{-1}}$ is the speed of the wind.

When the plane is travelling against wind, the ground speed of this plane (speed of the plane relative to the ground) would be $(x - y)\; {\rm km \cdot h^{-1}}$ .
When this plane is travelling in the same direction as the wind, the ground speed of this plane would be $(x + y)\; {\rm km \cdot h^{-1}}$ .

The question states that when going against the wind ( $v = (x - y)\; {\rm km \cdot h^{-1}}$ ,) the plane travels $6111\; {\rm km}$ in $9\; {\rm h}$ . Hence, $9\, (x - y) = 6111$ .

Similarly, since the plane travels $7911\; {\rm km}$ in $9\; {\rm h}$ when travelling in the same direction as the wind ( $v = (x + y)\; {\rm km \cdot h^{-1}}$ ,) $9\, (x + y) = 7911$ .

Add the two equations to eliminate $y$ . Subtract the second equation from the first to eliminate $x$ . Solve this system of equations for $x$ and $y$ : $x = 779$ and $y = 100$ .

Hence, the speed of this plane in still air would be $779\; {\rm km \cdot h^{-1}}$ , whereas the speed of the wind would be $100\; {\rm km \cdot h^{-1}}$ .

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1 year ago

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7nadin3 [17]

Answer:

C. The percentage of all homeowners that own at least one dog

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Sergeu [11.5K]

I believe it's 36 :)

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2 years ago

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