Answer:
Age of son = 6 years
Age of man = 5×6 = 30 years
Step-by-step explanation:
<u>GIVEN :-</u>
- A man is 5 times as old as his son. (In Present)
- 4 years ago , the man was 13 times as old as his son
<u>TO FIND :-</u>
- The present ages of the man & his son.
<u>SOLUTION :-</u>
Let the present age of son be 'x'.
⇒ Present age of man = 5x
4 years ago ,
Age of son = (Present age of son) - 4 = x - 4
Age of man = (Present age of man) - 4 = 5x - 4
The man was thirteen times as old as his son. So,
Now , solve the equation.
- Open the brackets in R.H.S.
- Take 5x to R.H.S. and -52 to L.H.S. Also , take care of their signs because they are getting displaced from L.H.S. to R.H.S. or vice-versa.
- Divide both the sides by 8
<u>CONCLUSION :-</u>
Age of son = 6 years
Age of man = 5×6 = 30 years
Yes
7.539 is greater than 7.344 by 0.195
hope this helps
What is the amount of cans so i can answer
It would be C.
For example, say 1 person comes. This would be x=1. Plugging this in gives you,
y=0.5 + 1.3
This shows that C is true since x is always going to be multiplied by 0.5.
1.3 would be the base amount of time it takes to arrange since if it the y-intercept.
Y=mx+b
m=slope
b=y intercept
we are given (3,-1)
one solution is x=3 and y=-1 or
when x=3 then y=-1
also slope=2
so
y=2x+b
subsitue 3 for x and -1 for y and solve for b
-1=2(3)+b
-1=6+b
subtract 6
-7=b
y=2x-7 is equation
answer is number 4