Answer:
The 2 numbers are 22 and 23
Step-by-step explanation:
let the two numbers be x and x+1
according to the question:
(x+1)^2 - x^2 = 45
x^2+1+2x - x^2 = 45
2x + 1 = 45
2x= 44
x = 22
the other number is x+1 = 22+1 = 23
therefore, the two consecutive numbers are 22 and 23
Hope it helped u....
16 n^2 -10n + 129 = 8n^2 -8
We collect the terms:
8n^2 -10n + 137 = 0
The steps for completing the square:
1) Move the "non X" (or "non N") term to the right:
8n^2 -10n = -137
<span>2)<span> Divide the equation by the coefficient of N² which in this case is 8
n^2 -1.2n = </span></span><span><span>-17.125
</span>
3) Take the coefficient of "N"; divide it by 2; square it; add it to both sides of the equation.
-1.2 / 2 = -.6
-.6^2 = .36
</span>
n^2 -1.2n +.36 = <span>-17.125
+.36
Take the square root of both sides:</span>
(n-.6)*(n-.6) = sq root(
<span>
<span>
<span>
-16.765
</span>
</span>
</span>
)
That's about as far as I can go.
1800
LCM of 10 and 15 = 30
LCM of 6 and 20 = 60
30(60) = 1800
Answer:
hope it helps
Step-by-step explanation: