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2 years ago

How does exhailing remove waste from the body? Explain the systems that make this happen‚ using complete sentences

Physics

1 answer:

aliina [53]2 years ago

3 0

Answer:

The lungs get rid of carbon dioxide and water vapor. The liver gets rid of bile, which, in addition to breaking down fats, is partially made up of the breakdown of red blood cells. The kidneys get rid of toxins from the blood. The large intestine gets rid of undigested food

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The displacement of a wave traveling in the positive x-direction is y(x, t)|= (3.5 cm)cos(2.7x − 92t), where x is in m and t is

zubka84 [21]

Answer

Given,

y(x, t) = (3.5 cm) cos(2.7 x − 92 t)

comparing the given equation with general equation

y(x,t) = A cos(k x - ω t)

A = 3.5 cm , k = 2.7 rad/m , ω = 92 rad/s

we know,

a) ω =2πf

f = 92/ 2π

f = 14.64 Hz

b) Wavelength of the wave

we now, k = 2π/λ

2π/λ = 2.7

λ = 2 π/2.7

λ = 2.33 m

c) Speed of wave

v = ν λ

v = 14.64 x 2.33

v = 34.11 m/s

5 0

2 years ago

Why aren’t the Appalachian Mountains still as tall as the Himalayas?

stealth61 [152]

Answer:

mountains are limited in their theoretical height by several processes. First is isostasy: the bigger a mountain gets, the more it weighs down its tectonic plate, so it sinks lower. ... Bottom line: mountains can get taller than Mount Everest in earth gravity, like the Appalachians probably did—but not much taller.

3 0

1 year ago

Read 2 more answers

A 45 N girl sits on a bench 0.6 meters off the ground. How much work is done on the bench?

ycow [4]

Answer: 27 joules

Explanation:

Work is done when force is applied on the bench over a distance. it is measured in joules.

Workdone = force x distance

= 45 N x 0.6 metres

= 27 joules

Thus, 27 joules of work is done on the bench.

6 0

2 years ago

To determine the height of a tall building such as Sears Tower in Chicago, Illinois a ball was dropped from the top of the build

Darya [45]

Answer:

The height of Sears Tower is 1448.5 feet.

Explanation:

<h3>We apply the free fall formula to the ball: </h3><h3> $y=v_{o} *t+\frac{1}{2} *g*t^{2}$ </h3><h3>y: The vertical distance the ball moves at time t </h3><h3> $v_{o}$ i: Initial speed </h3><h3>g=Gravity acceleration= $9.8*(\frac{\frac{1ft}{0.305m} }{s^{2} } )$ </h3>

Known information

We know that the vertical distance (y) that the ball moves in 9,5s is equal to height of Sears Tower (h).

Too we know that the ball is released from rest, then, $v_{0}$ =0